Optimal. Leaf size=222 \[ \frac{\log \left (5 (2 x+1)-\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )}{\sqrt{10 \left (2+\sqrt{35}\right )}}-\frac{\log \left (5 (2 x+1)+\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )}{\sqrt{10 \left (2+\sqrt{35}\right )}}-\sqrt{\frac{2}{5 \left (\sqrt{35}-2\right )}} \tan ^{-1}\left (\frac{\sqrt{10 \left (2+\sqrt{35}\right )}-10 \sqrt{2 x+1}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right )+\sqrt{\frac{2}{5 \left (\sqrt{35}-2\right )}} \tan ^{-1}\left (\frac{10 \sqrt{2 x+1}+\sqrt{10 \left (2+\sqrt{35}\right )}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right ) \]
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Rubi [A] time = 0.690727, antiderivative size = 222, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 7, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.318 \[ \frac{\log \left (5 (2 x+1)-\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )}{\sqrt{10 \left (2+\sqrt{35}\right )}}-\frac{\log \left (5 (2 x+1)+\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )}{\sqrt{10 \left (2+\sqrt{35}\right )}}-\sqrt{\frac{2}{5 \left (\sqrt{35}-2\right )}} \tan ^{-1}\left (\frac{\sqrt{10 \left (2+\sqrt{35}\right )}-10 \sqrt{2 x+1}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right )+\sqrt{\frac{2}{5 \left (\sqrt{35}-2\right )}} \tan ^{-1}\left (\frac{10 \sqrt{2 x+1}+\sqrt{10 \left (2+\sqrt{35}\right )}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right ) \]
Antiderivative was successfully verified.
[In] Int[Sqrt[1 + 2*x]/(2 + 3*x + 5*x^2),x]
[Out]
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Rubi in Sympy [A] time = 51.9155, size = 223, normalized size = 1. \[ \frac{\sqrt{10} \log{\left (2 x - \frac{\sqrt{10} \sqrt{2 + \sqrt{35}} \sqrt{2 x + 1}}{5} + 1 + \frac{\sqrt{35}}{5} \right )}}{10 \sqrt{2 + \sqrt{35}}} - \frac{\sqrt{10} \log{\left (2 x + \frac{\sqrt{10} \sqrt{2 + \sqrt{35}} \sqrt{2 x + 1}}{5} + 1 + \frac{\sqrt{35}}{5} \right )}}{10 \sqrt{2 + \sqrt{35}}} + \frac{\sqrt{10} \operatorname{atan}{\left (\frac{\sqrt{10} \left (\sqrt{2 x + 1} - \frac{\sqrt{20 + 10 \sqrt{35}}}{10}\right )}{\sqrt{-2 + \sqrt{35}}} \right )}}{5 \sqrt{-2 + \sqrt{35}}} + \frac{\sqrt{10} \operatorname{atan}{\left (\frac{\sqrt{10} \left (\sqrt{2 x + 1} + \frac{\sqrt{20 + 10 \sqrt{35}}}{10}\right )}{\sqrt{-2 + \sqrt{35}}} \right )}}{5 \sqrt{-2 + \sqrt{35}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((1+2*x)**(1/2)/(5*x**2+3*x+2),x)
[Out]
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Mathematica [C] time = 0.288042, size = 112, normalized size = 0.5 \[ \frac{2 \left (\sqrt{-2+i \sqrt{31}} \left (\sqrt{31}-2 i\right ) \tan ^{-1}\left (\frac{\sqrt{10 x+5}}{\sqrt{-2-i \sqrt{31}}}\right )+\sqrt{-2-i \sqrt{31}} \left (\sqrt{31}+2 i\right ) \tan ^{-1}\left (\frac{\sqrt{10 x+5}}{\sqrt{-2+i \sqrt{31}}}\right )\right )}{5 \sqrt{217}} \]
Antiderivative was successfully verified.
[In] Integrate[Sqrt[1 + 2*x]/(2 + 3*x + 5*x^2),x]
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Maple [B] time = 0.064, size = 486, normalized size = 2.2 \[ -{\frac{\sqrt{2\,\sqrt{5}\sqrt{7}+4}\sqrt{5}}{155}\ln \left ( -\sqrt{2\,\sqrt{5}\sqrt{7}+4}\sqrt{5}\sqrt{1+2\,x}+\sqrt{5}\sqrt{7}+10\,x+5 \right ) }-{\frac{4\,\sqrt{5}\sqrt{7}+8}{31\,\sqrt{10\,\sqrt{5}\sqrt{7}-20}}\arctan \left ({\frac{1}{\sqrt{10\,\sqrt{5}\sqrt{7}-20}} \left ( -\sqrt{2\,\sqrt{5}\sqrt{7}+4}\sqrt{5}+10\,\sqrt{1+2\,x} \right ) } \right ) }+{\frac{\sqrt{7}\sqrt{2\,\sqrt{5}\sqrt{7}+4}}{62}\ln \left ( -\sqrt{2\,\sqrt{5}\sqrt{7}+4}\sqrt{5}\sqrt{1+2\,x}+\sqrt{5}\sqrt{7}+10\,x+5 \right ) }+{\frac{ \left ( 2\,\sqrt{5}\sqrt{7}+4 \right ) \sqrt{5}\sqrt{7}}{31\,\sqrt{10\,\sqrt{5}\sqrt{7}-20}}\arctan \left ({\frac{1}{\sqrt{10\,\sqrt{5}\sqrt{7}-20}} \left ( -\sqrt{2\,\sqrt{5}\sqrt{7}+4}\sqrt{5}+10\,\sqrt{1+2\,x} \right ) } \right ) }+{\frac{\sqrt{2\,\sqrt{5}\sqrt{7}+4}\sqrt{5}}{155}\ln \left ( \sqrt{5}\sqrt{7}+10\,x+5+\sqrt{2\,\sqrt{5}\sqrt{7}+4}\sqrt{5}\sqrt{1+2\,x} \right ) }-{\frac{4\,\sqrt{5}\sqrt{7}+8}{31\,\sqrt{10\,\sqrt{5}\sqrt{7}-20}}\arctan \left ({\frac{1}{\sqrt{10\,\sqrt{5}\sqrt{7}-20}} \left ( 10\,\sqrt{1+2\,x}+\sqrt{2\,\sqrt{5}\sqrt{7}+4}\sqrt{5} \right ) } \right ) }-{\frac{\sqrt{7}\sqrt{2\,\sqrt{5}\sqrt{7}+4}}{62}\ln \left ( \sqrt{5}\sqrt{7}+10\,x+5+\sqrt{2\,\sqrt{5}\sqrt{7}+4}\sqrt{5}\sqrt{1+2\,x} \right ) }+{\frac{ \left ( 2\,\sqrt{5}\sqrt{7}+4 \right ) \sqrt{5}\sqrt{7}}{31\,\sqrt{10\,\sqrt{5}\sqrt{7}-20}}\arctan \left ({\frac{1}{\sqrt{10\,\sqrt{5}\sqrt{7}-20}} \left ( 10\,\sqrt{1+2\,x}+\sqrt{2\,\sqrt{5}\sqrt{7}+4}\sqrt{5} \right ) } \right ) } \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((1+2*x)^(1/2)/(5*x^2+3*x+2),x)
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{\sqrt{2 \, x + 1}}{5 \, x^{2} + 3 \, x + 2}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt(2*x + 1)/(5*x^2 + 3*x + 2),x, algorithm="maxima")
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Fricas [A] time = 0.25593, size = 1083, normalized size = 4.88 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt(2*x + 1)/(5*x^2 + 3*x + 2),x, algorithm="fricas")
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Sympy [A] time = 5.46564, size = 32, normalized size = 0.14 \[ 4 \operatorname{RootSum}{\left (1230080 t^{4} + 1984 t^{2} + 7, \left ( t \mapsto t \log{\left (9920 t^{3} + 8 t + \sqrt{2 x + 1} \right )} \right )\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((1+2*x)**(1/2)/(5*x**2+3*x+2),x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{\sqrt{2 \, x + 1}}{5 \, x^{2} + 3 \, x + 2}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(sqrt(2*x + 1)/(5*x^2 + 3*x + 2),x, algorithm="giac")
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